Go example to convert binary to text and text to binary

convert_binary_text.go

package main

import (
	"fmt"
	"strconv"
	"strings"
)

func textToBinary(s string) string {
	var b string
	for _, c := range s {
		b = fmt.Sprintf("%s %.8b", b, c)
	}
	return strings.TrimSpace(b)
}

func binaryToText(s string) (x string) {
	b := make([]byte, 0)
	for _, s := range strings.Fields(s) {
		n, _ := strconv.ParseUint(s, 2, 8)
		b = append(b, byte(n))
	}
	x = string(b)
	return
}

func numberToBinary(n int) string {
	return fmt.Sprintf("%08b", n)
}

func binaryToNumber(s string) int {
	num, err := strconv.ParseInt(s, 2, 0)
	if err != nil {
		return 0
	}

	return int(num)
}

func leftShiftBinary(binaryStr string, shiftAmount int) string {
	paddedBinaryStr := binaryStr + strings.Repeat("0", shiftAmount)
	resultBinary := paddedBinaryStr[shiftAmount:]
	return resultBinary
}

func rightShiftBinary(binaryStr string, shiftAmount int) string {
	paddedBinaryStr := strings.Repeat("0", shiftAmount) + binaryStr
	resultBinary := paddedBinaryStr[:len(paddedBinaryStr)-shiftAmount]
	return resultBinary
}

func main() {
	text := "Rodolfo"
	tToB := textToBinary(text)
	fmt.Println(tToB)

	nText := binaryToText(tToB)
	fmt.Println(nText)

	nToB := numberToBinary(2)
	fmt.Println(nToB)

	bToN := binaryToNumber(nToB)
	fmt.Println(bToN)

	afterLeftShift := leftShiftBinary(nToB, 1)
	fmt.Println(afterLeftShift)

	bToN2 := binaryToNumber(afterLeftShift)
	fmt.Println(bToN2)

	afterRightShift := rightShiftBinary(afterLeftShift, 1)
	fmt.Println(afterRightShift)
}