comparison between isAnagram function (one implemented using sorted and other with hashmaps)

isAnagramTest.py

import random
import string
import timeit

def isAnagramSorted(str1, str2):
    return sorted(str1) == sorted(str2)

def isAnagram(str1, str2):
    stringMap = {}
    for c in str1:
        count = stringMap.get(c) or 0
        count += 1
        stringMap[c] = count
    for c in str2:
        count = stringMap.get(c)
        if (count):
            if (count < 1):
                return False
            count -= 1
            stringMap[c] = count
    return True

def getAnagramStrings(strlen):
    str1 = ''

    for i in range(strlen):
        str1 += string.ascii_letters[random.randint(0, 51)]

    str2 = ''.join(random.sample(str1,len(str1)))

    return (str1, str2)

if __name__ == '__main__':

    for i in range(100, 1000, 100):
        str1, str2 = getAnagramStrings(i)
        print('---------------------------------------------\n')
        print('strlen: {}'.format(i))
        print('isAnagram: {}'.format(timeit.timeit('isAnagram(str1, str2)', globals=globals(), number=1000)))
        print('isAnagramSorted: {}'.format(timeit.timeit('isAnagramSorted(str1, str2)', globals=globals(), number=1000)))
        print('---------------------------------------------\n')

    for i in range(1000, 10000, 1000):
        str1, str2 = getAnagramStrings(i)
        print('---------------------------------------------\n')
        print('strlen: {}'.format(i))
        print('isAnagram: {}'.format(timeit.timeit('isAnagram(str1, str2)', globals=globals(), number=1000)))
        print('isAnagramSorted: {}'.format(timeit.timeit('isAnagramSorted(str1, str2)', globals=globals(), number=1000)))
        print('---------------------------------------------\n')