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February 12, 2013 11:44
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coin change problem(classical dynamic programming problem)
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/* | |
Coin change problem (classical dynamic programming problem) | |
@author : rohit | |
*/ | |
#include <iostream> | |
#include <stdio.h> | |
#include <vector> | |
#define INF 1e9 | |
using namespace std; | |
vector<int> v; | |
int arr[128]; | |
int Min[10001]; | |
int rdp(int n){ | |
if(n<0) return INF; | |
if(n==0) return 0; | |
if(arr[n]!=-1) | |
return arr[n]; | |
int ans=INF; | |
for(int i=0;i<v.size();i++) | |
ans=std::min(ans,rdp(n-v[i])); | |
return arr[n]=ans+1; | |
} | |
int idp(int s,int n){ | |
for(int i=0;i<10001;i++) | |
Min[i]=INF; | |
Min[0]=0; | |
for(int i=1;i<=s;i++){ | |
for(int j=0;j<n;j++){ | |
if(v[j]<=i && (Min[i-v[j]]+1)<Min[i]) | |
Min[i]=Min[i-v[j]]+1; | |
} | |
} | |
return Min[s]; | |
} | |
int main(){ | |
int n; | |
cin>>n; | |
for(int i=0;i<n;i++){ | |
int x; | |
cin>>x; | |
v.push_back(x); | |
} | |
int change; | |
cin>>change; | |
for(int i=0;i<128;i++) | |
arr[i]=-1; | |
cout<<rdp(change)<<endl; | |
cout<<idp(change,n)<<endl; | |
return 0; | |
} |
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