Task

"""



The function accepts a string as a parameter.
The function returns a dictionary, so each organ in it is a key consisting of a key: 
a character from the string passed (not including spaces), and an array: 
the number of times the character appears in the string.



magic_str = "abra cadabra"
count_chars(magic_str)
{'a': 5, 'b': 2, 'r': 2, 'c': 1, 'd': 1}

"""





#################        made by three loops       ############################################



"""
magic_str = "abra cadabra"
count_chars(magic_str)
{'a': 5, 'b': 2, 'r': 2, 'c': 1, 'd': 1}
"""




# The function returns a dictionary, so each organ in it is a key consisting of a key
def count_chars(my_str):
    new_magic = magic_str.replace(" ","") # Deleting spaces
    z = len(new_magic) # Length of the new str list with no spaces
    a = "" # New variable for str made
    x = 0 # To start the loop
    while x < z: # First loop
        if not (new_magic[x] in a): # Does the word from loop in the new made list?
            a += new_magic[x] # If not in the list it will add the string to the new variable list
            c = [] # New variable for list made
            y = len(a) # The length of the new made variable "a" list of str
            i = 0 # Zero point of second while loop 
            while i < y: # Second loop under first loop
                b = new_magic.count(a[i]) # A loop index run inside the list variable "a" and counting how many times it's exists inside the new_magic list and moving the new list of counted numbers to variable "b"
                i += 1
                c.append(b) # Adding the variable "b" results into new made list under variable "c"
            result = {} # New variable for dict made
            y = len(a) # The length of the new made variable "a" list of str
            i = 0 # Zero point of third while loop 
            while i < y: # Third loop under second loop
                result [a[i]] = c[i] # A loop index run inside the list variable "a" and "c" and adding them to the new dictionary list that i made
                i += 1
        x += 1
    return result



def main():	
    <call the function>

if __name__ == "__main__":
    main()




#################           ############################################
####################       made by one loop        #####################

"""
INPUT:
magic_str = "abra cadabra"

INPUT:
count_chars(magic_str)

SUPPOSE OUTPUT:
{'a': 5, 'b': 2, 'r': 2, 'c': 1, 'd': 1}
"""


def count_chars(my_str):
    result = {}
    z = len(my_str)
    a = ""
    i = 0
    while i < z:
        if my_str[i] != " ":
            a = my_str.count(my_str[i])
            result [my_str[i]] = a
        i += 1
    return result




def main():	
    <call the function>

if __name__ == "__main__":
    main()