Task

"""
We are nearing the end of the courses and at this stage we are in contact.

The function accepts as a dictionary parameter.
The function returns a new dictionary with "Reverse" mapping: Each key in the transferred dictionary 
is a value in the returned dictionary and each value in the transferred dictionary is a key in the returned dictionary.

Instructions:

- The flip between keys and values ​​can create keys that appear more than once. Therefore, 
display the values ​​in the dictionary returned as a list, which may contain one or more entries.
- Returned lists should be sorted (the values ​​in the dictionary may be of the same type).
- In the last chapter you got to know a number of actions when working with dictionary type objects. 
In this exercise, read on the web for useful methods of working with a dictionary and explore additional actions for yourself.


Example of inverse_dict run function:


course_dict = {'I': 3, 'love': 3, 'self.py!': 2}
inverse_dict(course_dict)
{3: ['I', 'love'], 2: ['self.py!']}

"""



"""
INPUT:
course_dict = {'I': 3, 'love': 3, 'self.py!': 2}

RUN:
inverse_dict(course_dict)

OUTPUT:
{3: ['I', 'love'], 2: ['self.py!']}
"""




"""
The function returns a new dictionary with "Reverse" mapping: Each key in the transferred dictionary 
is a value in the returned dictionary and each value in the transferred dictionary is a key in the returned dictionary.
"""
def inverse_dict(my_dict):
    a = [] # New list
    b = list(course_dict) # Laking a new variable and saving the dictionary list there
    c = [] # New list
    d = [] # New list
    result = {} # New dict
    z = len(b)-1 # Length of the 
    i = 0 # Zero the loop
    for value in course_dict.values(): # Getting the values from the dict
        a.append(value) # Adding the values to the variable "a"
    while i < z: # Running the loop
 # Condition: If the amount of the number from the list "a" is more than 1, and numbers equal to the number of the dict key, ......
 # .....and the word not in the dictionary already
        if a.count(a[i]) > 1 and a[i] == course_dict[b[i]] and not(b[i] in c):
            c.append(b[i]) # Adding the word to variable "c"
            result[a[i]] = c # Adding the word from variable "c" to my new made dict "result"
        i += 1 # VERY IMPORTANT look where the +1 is located in the loop or the last condition not gonna work. 
 # Condition: If the amount of the number from the list "a" is equal to 1, and numbers equal to the number of the dict key, ......
 # .....and the word not in the dictionary already
        if a.count(a[i]) == 1 and a[i] == course_dict[b[i]] and not(b[i] in d):
            d.append(b[i]) # Adding the word to variable "d"
            result[a[i]] = d # Adding the word from variable "d" to my new made dict "result"
    return result






def main():	
    <call the function>

if __name__ == "__main__":
    main()