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December 16, 2015 18:58
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3n+1 assignment sollution
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function isOdd(n){ | |
return (n & 1); | |
} | |
function getStepCount(n, c){ | |
var count = c | 0; | |
count++; | |
if(n < 1){ | |
return 0; | |
}else if(n == 1){ | |
return count; | |
}else if(isOdd(n)){ | |
return getStepCount(3*n+1, count); | |
}else{ | |
return getStepCount(n/2, count) ; | |
} | |
} | |
function getMaximumStep(i,j){ | |
if(i>j){ | |
return "Wrong Input"; | |
} | |
var data = { | |
max_step:0, | |
max_step_n:false | |
}; | |
for(n=i; n<=j; n++){ | |
var current_steps = getStepCount(n); | |
if( current_steps > data.max_step ){ | |
data.max_step = current_steps; | |
data.max_step_n = n; | |
} | |
} | |
return "Maximum Step (" + data.max_step + ") Needed for number : " + data.max_step_n; | |
} | |
var n= prompt('Please enter value of i,j',''); | |
n = n.split(','); | |
document.write(getMaximumStep(n[0],n[1])); |
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