Created
October 14, 2016 11:55
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pycon2016 STX Next Tic Tac Toe golf
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| def result(O): | |
| r='D' | |
| for d in(O,zip(*O[::-1])): | |
| if d[0][0]==d[1][1]==d[2][2]:r=d[0][0] | |
| for R in d: | |
| if len(set(R))<2: | |
| r=R[0] | |
| return r |
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