Examples for the parallel comparison of the ES5 and ES6 syntaxes, used for creating object constructors in JS.
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January 18, 2021 16:20
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JS | Prototypes - ES5 vs ES6 syntax
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function Product(name, price) { | |
this.name = name; | |
this.price = price; | |
} | |
Product.prototype.nameAndPrice = function() { | |
console.log( | |
"The product's name is: " + this.name, | |
"and the product's price is: " + this.price, | |
); | |
}; | |
// Extend Product to Toy | |
function Toy(name, price, brand) { | |
Product.call(this, name, price); | |
this.brand = brand; | |
} | |
// Extend the prototype | |
// Object.create() is used to connect the `Toy.prototype.__proto__` to `Product.prototype` | |
// When using class the same thing is done automatically when using keyword `extends` | |
Toy.prototype = Object.create(Product.prototype); | |
Toy.prototype.constructor = Toy; | |
// The Object.create() method creates a new object, using an existing object as the prototype of the newly created object. | |
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class Product { | |
constructor(name, price) { | |
this.name = name; | |
this.price = price; | |
} | |
nameAndPrice() { | |
console.log( | |
"The product's name is: " + this.name, | |
"and the product's price is: " + this.price, | |
); | |
} | |
} | |
class Toy extends Product { | |
constructor(name, price, brand) { | |
super(name, price); // `super` is equivalent to: `Product.call(this, name, price)` | |
this.brand = brand; | |
} | |
} | |
// We don't have to explicitly "extend the prototype" like with the ES5 function constructors. | |
// This is done automatically by JS when using the keyword `extends`. |
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