Count Digits In A Number

Faq

Q1) Why is the while loop condition (n>0) not (n>=0)?
ans: If n==0 then there is no more digit present so, if you keep (n>=0) then it will give one more count extra.
     Therefore, we are using n>0.
     
Q2) Why while loop not for loop?
ans: We can use any of the loop,even if you use for loop it will give you same solution.

Q3) why are we doing n=n/10?
ans: When we divide a number by 10, the digit in that number is decrease by one so, by dividing the count of digit present in that number.

Q4) Difference between count++ and count=count+1?
ans: Both count++ and count = count+1 means the variable count is increase by one.
 

Hints

Hint 1: Try to use division method
Hint 2: Remember to increase count
Hint 3: Beware of Overflow

Mcq

Q1) Fill the blank in according to Counts digit problem ?
    while(n>0)
      {
        count++;
        _______;
      }
    
    a) n=n%10
    b) n=n*10
    c) n=n/10
    d) n=n%10+1
    
ans : d)

Q2) choose the correct one:
    while(n>0)
    {
       count++;
    }
    System.out.println(count);
    
    a) 1
    b) compilation error
    c) runtime error
    d) 10

ans: c)

Q3) choose the correct output:
    int n=1234;
    int count=0;
    while(true)
    {
        count++;
        if(count>3)
        break;
        if(count>2)
        break;
        n=n/10;
    }
    System.out.print(count);
    
    a) 2
    b) 4
    c) 3
    d) 0

ans: c)