remove_array_odds-5.js

/**
    Code Challenge Needed:
        Using Javascript, given an array of n integers (example: [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 100, 112, 113] ), remove all odd numbers, leaving only the even numbers.
    Rules:
        NO LOOPING. This means native methods, or libraries that loop for you are not allowed either.
    Supply the answer on github via Gist
**/

var numbersArray =  [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 100, 112, 113];


//initial array
console.log('The original numbers array was : ', numbersArray);

//this code is just one more variation( looping with a for... I know :) ) but despite the polemic about performace this kind of solutions are more clear, more maintainable and reusable code also are more easy to trace
function getEvens(array){
    let position = 0,
        arrayLength = array.length; 

    for (var i = 0; i < arrayLength; i++) {
        if ( !(array[i] % 2) ) {
            array[position++] = array[i]; 
        }
    }
    array.length = position;
    return array;
}


var evensArray = getEvens(numbersArray);

//final array
console.log('The evens numbers are : ', evensArray);