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May 11, 2012 20:24
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'We solve the Zebra Puzzle with the help of a MIP model and SCIP
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'''We solve the Zebra Puzzle with the help of a MIP model and SCIP''' | |
from zibopt import scip | |
# see https://en.wikipedia.org/wiki/Zebra_Puzzle | |
houses = range(5) | |
nations = ['England', 'Japan', 'Norway', 'Spain', 'Ukraine'] | |
pets = ['dog', 'fox', 'horse', 'snails', 'zebra'] | |
drinks = ['coffee', 'milk', 'orange juice', 'tea', 'water'] | |
colors = ['blue', 'green', 'ivory', 'red', 'yellow'] | |
cigarettes = ['Chesterfield', 'Kool', 'Lucky Strike', 'Old Gold', 'Parliament'] | |
s = scip.solver() | |
# create assignment variables for every pair of item, house | |
a = dict() | |
for item in sum([nations, pets, drinks, colors, cigarettes], []): | |
a[item] = [ s.variable(scip.BINARY) for _ in houses ] | |
def house_sum(item): | |
'''Express the actual house number in terms of the assignment''' | |
return sum(house * a[item][house] for house in houses) | |
# add assignment constraints: | |
# every house has exactly one item of every category, and vice versa | |
for cat in [nations, pets, drinks, colors, cigarettes]: | |
for house in houses: | |
s += sum(a[item][house] for item in cat) == 1.0 | |
for item in cat: | |
s += sum(a[item][house] for house in houses) == 1.0 | |
# add rest of the constraints: | |
# | |
# (There are five houses.) | |
# The Englishman lives in the red house. | |
s += house_sum('England') == house_sum('red') | |
# The Spaniard owns the dog. | |
s += house_sum('Spain') == house_sum('dog') | |
# Coffee is drunk in the green house. | |
s += house_sum('coffee') == house_sum('green') | |
# The Ukrainian drinks tea. | |
s += house_sum('Ukraine') == house_sum('tea') | |
# The green house is immediately to the right of the ivory house. | |
s += house_sum('green') == house_sum('ivory') + 1 | |
# The Old Gold smoker owns snails. | |
s += house_sum('Old Gold') == house_sum('snails') | |
# Kools are smoked in the yellow house. | |
s += house_sum('Kool') == house_sum('yellow') | |
# Milk is drunk in the middle house. | |
s += a['milk'][2] == 1 | |
# The Norwegian lives in the first house. | |
s += a['Norway'][0] == 1 | |
# The man who smokes Chesterfields lives in the house next to the | |
# man with the fox. | |
helper = s.variable(scip.BINARY) | |
s += house_sum('Chesterfield') - house_sum('fox') == 2 * helper - 1 | |
# Kools are smoked in the house next to the house where the horse is | |
# kept. [should be "... a house ...", see discussion below] | |
helper = s.variable(scip.BINARY) | |
s += house_sum('Kool') - house_sum('horse') == 2 * helper - 1 | |
# The Lucky Strike smoker drinks orange juice. | |
s += house_sum('Lucky Strike') == house_sum('orange juice') | |
# The Japanese smokes Parliaments. | |
s += house_sum('Japan') == house_sum('Parliament') | |
# The Norwegian lives next to the blue house. | |
helper = s.variable(scip.BINARY) | |
s += house_sum('Norway') - house_sum('blue') == 2 * helper - 1 | |
# In the interest of clarity, it must be added that each of the five | |
# houses is painted a different color, and their inhabitants are of | |
# different national extractions, own different pets, drink different | |
# beverages and smoke different brands of American cigarets [sic]. One | |
# other thing: in statement 6, right means your right. | |
sol = s.maximize() | |
def house_sol(item): | |
'''Get the house number from the solution''' | |
house = sum(house * sol[ a[item][house] ] for house in houses) | |
return '%s is at house %d' % (item, round(house)) | |
def item_sol(cat, house): | |
'''Get the item of the category at some house''' | |
res = [item for item in cat if sol[ a[item][house] ] > 0.5] | |
assert len(res) == 1 | |
return res[0] | |
# Now, who drinks water? | |
print(house_sol('water')) | |
# Who owns the zebra? | |
print(house_sol('zebra')) | |
print() | |
# all results in tabular form | |
for cat in [colors, nations, drinks, cigarettes, pets]: | |
print(' | '.join('%-12s' % item_sol(cat, house) for house in houses)) |
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