python.除法.py

# coding:utf-8
import math
print "2/2=1        == " , 2/2
print "3/2=1.5      == " , 3/2
print "6/5=1.2      == " , 6/5
print "1.2/10=0.12  == " , 1.2/10
print "1.2/0.01=120 == " , 1.2/0.01
print "1.0/1.0=1    == " , 1.0/1.0
print "-------取小数-------"	# 据说 P3 可以直接取小数 , P2 规则是整数相除得出整数
print "float(3/2)=1.5        == " , float(3/2)
print "float(3)/2=1.5        == " , float(3)/2
print "3/float(2)=1.5        == " , 3/float(2)
print "float(3)/float(2)=1.5 == " , float(3)/float(2)
print "-------四舍五入-------"
print "round(1.5)=2            == " , round(1.5)
print "round(3/2)=1.5=2        == " , round(3/2)
print "round(float(3)/2)=1.5=2 == " , round(float(3)/2)
print "round(1.2)=1            == " , round(1.1)
print "round(6/5)=1.2=1        == " , round(6/5)
print "round(float(6)/5)=1.2=1 == " , round(float(6)/5)
print "--------进一法,有小数就进1取整-------","需要先 import math"
print "math.ceil(1.5)=2            == " , math.ceil(1.5)
print "math.ceil(1.1)=2            == " , math.ceil(1.1)
print "math.ceil(3/2)=1.5=2        == " , math.ceil(3/2) # 这样是取不到的 要学下面
print "math.ceil(float(3)/2)=1.5=2 == " , math.ceil(float(3)/2)
print "-------进一法,方法2"
print "UP(A/B) = int((A+B-1)/B)"
print "3/2=1.5=2 >> int( (3+2-1)/2 ) == " , int( (3+2-1)/2 ) # 这个方法就不用老是 float() 了
print "6/5=1.2=2 >> int( (6+5-1)/2 ) == " , int( (6+5-1)/5 ) # 问题是这个方法怎么个意思 , 为什么会这样?
print "-------小数取整数部分------"
print "int(1.5),int(1.2) == " , int(1.5) , "," , int(1.2) 
print "int(3/2),int(6/5) == " , int(3/2) , "," , int(6/5) # 这里常量都是整数 , 所以变的没有意义