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@rustyconover
Created May 5, 2015 20:44
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Collatz sequence counter
def collatz_count_until_1(n):
count = 0
while n != 1:
if n % 2 == 0:
n = n / 2
else:
n = (3 * n) + 1
count += 1
return count
max = None
for x in range(1, 100000):
length = collatz_count_until_1(x)
if max == None or max[0] < length:
max = (length, x)
print "Maximum stopping distance %d, starting number %d" % (max[0], max[1])
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