Created
November 30, 2010 21:27
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Pascal's Triangle in scala
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// An exercise using scala to output a nicely formatted Pascal's triangle | |
import scala.math.max | |
// Define an extractor for Int so we can match below | |
object Int { | |
def unapply(s:String) : Option[Int] = try { | |
Some(s.toInt) | |
} catch { | |
case _ : java.lang.NumberFormatException => None | |
} | |
} | |
object Pascal { | |
val usage = """ | |
Usage: Pascal rows | |
""" | |
def main(args:Array[String]) { | |
if (args.length == 0) | |
println(usage) | |
for (a <- args) a match { | |
case Int(r) => printTriangle(r) | |
case s : String => println(s + " is not a whole number") | |
} | |
} | |
/** | |
* Computes the value at row r and column c | |
*/ | |
def v(r:Int, c:Int) : Int = | |
if (c == 0) | |
1 | |
else | |
v(r, c-1) * (r-c)/c | |
def printRow(r:Int, seplen:Int) = { | |
for (col <- 0 to r) { | |
if (col > 0) | |
print(" " * seplen) | |
val n = v(r+1, col) | |
print((" " * (seplen - n.toString.length)) + n ) | |
} | |
println() | |
} | |
def printTriangle(rows:Int) = { | |
// Figure out how many spaces to separate numbers | |
var largest = 1 | |
for (col <- 0 to rows) | |
largest = max(largest, v(rows+1, col)) | |
val seplen = largest.toString.length | |
val sep = " " * seplen | |
for (r <- 0 to rows) { | |
print(sep * (rows-r)) | |
printRow(r, seplen) | |
} | |
} | |
} |
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