SICP Exercise 1.5

gistfile1.txt

;; SICP 1.5

;; Given:
;;
;;     (define (p) (p))
;;
;;     (define (test x y)
;;       (if (= x 0)
;;           0
;;           y))
;;     (test 0 (p))
;;
;; Since applicative order evaluates the arguments before calling the
;; function, the (p) expression results in an infinite recursion.  And
;; since scheme has TCO, the interpreter will enter an infinite loop.