Find three numbers in an array that sum to the specified number

findTriplets.js

function findTriplets(arr, n) {
  let idx2, idx3;
  arr.sort((a, b) => a - b); // sort arr in ascending order
  
  for(let i = 0; i < arr.length - 2; i++) {
    idx2 = i + 1; // index of the first element in the remaining list of elementss
    idx3 = arr.length - 1; // index of the last element
    
    while(idx2 < idx3) {
      if(arr[i] + arr[idx2] + arr[idx3] == n) {
        console.log(`${arr[i]} + ${arr[idx2]} + ${arr[idx3]} equals ${n}`);
        return true;
      } else if (arr[i] + arr[idx2] + arr[idx3] < n) {
        idx2++; // increment the second idx to a higher number
      } else { // arr[i] + arr[idx2] + arr[idx3] > n
        idx3--; //decrement the third idx to a lesser number
      }
    }
  }
    return false;
}

findTriplets([1, 4, 45, 6, 10, 8], 24);