Codewars.com JS 'kata': Sort ascending odd numbers but even numbers must be on their places.

odd_sort.js

//TASK
You have an array of numbers.
Your task is to sort ascending odd numbers but even numbers must be on their places.

Zero isn't an odd number and you don't need to move it. If you have an empty array, you need to return it.

//EXAMPLE
sortArray([5, 3, 2, 8, 1, 4]) == [1, 3, 2, 8, 5, 4]


// SOLUTION
function sortArray(array) {

  var odd = array.filter(is_odd).sort(ascending);
  return array.map(replace_odd_inorder);


  function ascending(a, b) {

    return a > b;
  }

  function is_odd(num) {

    return num % 2;
  }

  function replace_odd_inorder(num) {

    return is_odd(num) ? odd.shift() : num;
  }
}

the ascending function has no importance and it doesn't make the code work so instead, you can keep it and make it return a-b or do all this in the body of sort function itself