Check whether a schedule is conflict serializable or not

conflict_serializable.py

# schedule 

schedule = "r1(x) r1(y) w2(x) w1(x) r2(y)".split(' ')
final_schedule = {}
cycles = {}

i_index = 0

for i in schedule:
	i_index += 1
	i_operation_type, i_transaction, i_operator = i[0], i[1], i[3]
	j_index = 0
	for j in schedule:
		j_index += 1
		j_operation_type, j_transaction, j_operator = j[0], j[1], j[3]
		if((i_transaction != j_transaction) and (i_operator == j_operator) and (i_operation_type+''+j_operation_type != 'rr') and j_index > i_index):
			if(i_transaction + '' + j_transaction not in final_schedule.values()):
				final_schedule[i + '-->' + j] = i_transaction + '' + j_transaction

# print(final_schedule)
						
for k,v in final_schedule.items():
	for k1,v1 in final_schedule.items():
		if(v == v1[::-1]):
			cycles[k] = v

print("Schedule: ")
for k,v in final_schedule.items():
	print('T'+v[0]+' --> '+'T'+v[1])

if(len(cycles)):
	print("Cycles found: ")
	for k,v in cycles.items():
		print('T'+v[0]+' --> '+'T'+v[1], end=" ")