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Dere Sagar sagardere

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var async = require('async')
async function f() {
let promise = new Promise((resolve, reject) => {
setTimeout(() => resolve("done!"), 1000)
});
let result = await promise; // wait till the promise resolves (*)
I/P: How many rows: 5
O/P:
@ 1 1 1 1
2 @ 2 2 2
3 3 @ 3 3
4 4 4 @ 4
5 5 5 5 @
//Logic
#include <stdio.h>
#include<stdio.h>
//#include<conio.h>
int main( )
{
int r,c,askey,sp,num;
printf("\n\n\tC PROGRAM TO PRINT REVERSE PYRAMID OF ALPHABETS \n");
printf("\nEnter the number of rows you want to show in your reverse pyramid : ");
scanf("%d",&num);
printf("\n\n\n");
for( r=num; r>=1; r-- )
#include <stdio.h>
void main()
{
int i,j,askey;
printf("\n\nPrint the 3*3 matrix from i to j\n");
printf("---------------------------------\n");
askey=105;
#include<stdio.h>
void main()
{
int rows,starNo,spaceNo;
printf("Enter Rows:\n");
scanf("%d",&rows);
for(int i=1;i<=rows;i++)
{
//Input
var arr1 = [1,3,2,4,0,9,3,5];
var arr2 = [0,9,2,2,7,5];
//output
var outputData = [ 2, 0, 9, 5 ];
//Answer
//1st way
var answer2 =[];
for(var num in arr1){
import java.util.Scanner;
public class pattern {
public static void printTriagle(int n)
{
int temp = n;
for(int i=0;i<n;i++) {
for(int j=0;j<n*2;j++) {
if(i==0) {
/*Input Value : Any number n = 5;
Output:
5555555555
4444**4444
333****333
22******22
1********1
*/
//Swap "1-st Array elements to last" and "Last element of array to 1-st"
var array = [33,535,5,345,3,4,5,3,5,34,5,435];
console.log("Before Swapping : " , array);
if(array.length != 0){
var last = array.pop();
var first = array[0];
// In switch statements if you are not add break statements
// after the end of case statements then all cases are executed by defaults
var number = 3;
switch(number){
case 1:
console.log("The number is one");
break;
case 2: