microsoft internship problem

microsoft internship problem.cpp

/*

1) Given a string, you have to check if it is a valid number or not.(The number can be signed, floating point/integer).
If it is a number return true else return false.
The constraints were :-
i) No decision statements allowed (No if-else,no switch-case).
ii) No ternary conditional operators allowed (? : not allowed).
iii) No looping statements allowed (No for/while/do-while).


*/

#include<iostream>
using namespace std;
bool dot=false;
bool endt=false;
bool finalr=true;

bool isdot(char c)
{

    return(c=='.'&&(!dot)&&(dot=true));
}
bool validno(char c)
{
    return(c=='0'||c=='1'||c=='2'||c=='3'||c=='4'||c=='5'||c=='6'||c=='7'||c=='8'||c=='9');
}

bool rec(char *s)
{

    endt=*s=='\0';

    bool thisis=endt||validno(*s)||isdot(*s);
    finalr=finalr&&thisis;
    bool ttm=(*s=='.')&&(*(s+1)=='\0')&&(finalr=false);
    s++;

    bool tm=(!endt)&&rec(s);

    return(finalr);

}
bool check(char s[])
{
    dot=(s[0]=='.');
    bool frst=s[0]=='-'||s[0]=='+'||dot||validno(s[0]);
    bool tm=(*(s+1)=='\0')&&(*s=='.'||*s=='+'||*s=='-')&&(finalr=false);
    return(frst&&rec(&s[1]));


}

int main()
{
dot=false;
endt=false;
finalr=true;

char s[1000];
cin>>s;
cout<<check(s);
main();
}