Created
August 29, 2022 15:46
-
-
Save salomaestro/c29c6313415ed86308dab703615b4529 to your computer and use it in GitHub Desktop.
File for recursively find a solution to a given function f on a interval [a, b] using the Intermediate Value Problem
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
import matplotlib.pyplot as plt | |
import numpy as np | |
class Node: | |
def __init__(self, boundary: tuple, depth: int, right: bool): | |
self.boundary = boundary | |
self.depth = depth | |
self.right = right | |
self.left = not right | |
def __str__(self): | |
return f"Node(boundary={self.boundary}, depth={self.depth}, direction={'right' if self.right else 'left'})" | |
def __repr__(self): | |
return f"Node(boundary={self.boundary}, depth={self.depth}, direction={'right' if self.right else 'left'})" | |
class Tree: | |
def __init__(self, func, leftbound, rightbound): | |
self.func, self.leftbound, self.rightbound = func, leftbound, rightbound | |
self.nodes = [] | |
def append(self, node: Node): | |
self.nodes.append(node) | |
def __str__(self): | |
return f"Tree(nodes={self.nodes})" | |
def __repr__(self): | |
return f"Tree(nodes={self.nodes})" | |
def draw(self): | |
fig, ax = plt.subplots(1, 1) | |
x = np.linspace(self.leftbound, self.rightbound, 100) | |
y = self.func(x) | |
ax.axhline(y=0, color='k') | |
ax.axvline(x=0, color='k') | |
ax.plot(x, y) | |
increment = 0.05 | |
for node in self.nodes: | |
py = node.boundary | |
px = (increment, increment) | |
ax.scatter(py, px, color='r') | |
increment += 0.1 | |
plt.show() | |
def recursive_bisect(f, a, b, n): | |
tree = Tree(f, a, b) | |
def recursive_bisect_exec(f, a, b, i): | |
fa = f(a) | |
fb = f(b) | |
c = (a + b) / 2 | |
fc = f(c) | |
# Trivial case | |
if i == 0: | |
return c | |
if fa * fc < 0: | |
tree.append(Node((a, c), n-i, False)) | |
return recursive_bisect_exec(f, a, c, i-1) | |
elif fc * fb < 0: | |
tree.append(Node((c, b), n-i, True)) | |
return recursive_bisect_exec(f, c, b, i-1) | |
else: | |
return "no root" | |
return recursive_bisect_exec(f, a, b, n), tree | |
if __name__ == "__main__": | |
f = lambda x: x**2 - x - 1 | |
approx_root, tree = recursive_bisect(f, -1, 2, 10) | |
print(tree) | |
tree.draw() |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment