parsepom.xml

parsepom.xml

// Parse pom.xml and print all dependency elements in single line for gradle use instead.
// Zemian Deng 11/1/2012
depMap = [:].withDefault{ [] }
project = new XmlParser().parse("pom.xml")
project.dependencies[0].each{ dependency ->
	line = "'" + dependency.groupId.text() + ":" +
		dependency.artifactId.text() + ":" + 
		dependency.version.text() + "'"
	scope = dependency.scope.text() ?: 'compile'
	depMap[scope] << line
}
depMap.entrySet().sort{ it.key }.each{ entry ->
	scope = entry.key
	depList = entry.value
	println scope + "("
	println depList.collect{ '  ' + it }.join(",\n")
	println ")"
}