Created
February 21, 2021 08:07
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Alternating Characters HackerRank Solution
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| def alternatingCharacters(s): | |
| count=0 | |
| for i in range(1,len(s)): # We start from 1 as there is no previous charcter for 0th index | |
| if s[i]==s[i-1]: # If current character is same as previous charcter | |
| count+=1 | |
| return count |
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