ffmpeg last frame of video

ffmpeg last frame video

#!/bin/bash

fn="$1"
of=`echo $1 | sed s/mp4/jpg/`

lf=`ffprobe -show_streams "$fn" 2> /dev/null | grep nb_frames | head -1 | cut -d \= -f 2`
rm -f "$of"
let "lf = $lf - 1"
ffmpeg -i $fn -vf select=\'eq\(n,$lf\) -vframes 1 $of

Thanks for being the only one on the net to provide the best way to do this, which is to find the number of the last frame. Everyone else, including the genii at stack*, did this by using timestamps.

Handy. Saved me a lot of work. Thanks.

Thanks for sharing!

Thanks for sharing! You could save future users some headache by adding a safety check before you run rm -f ...

Something like:

if [ "$fn" == "$of" ]; then echo "Only accepts MP4"; exit 1; fi

Otherwise, any input file that isn't an mp4 will be permanently deleted.