Windows batch file to start an exe and check its result

runAndCheck.bat

::Test pass criteria: Exe has to finish within maxExeRunTime_s and exe output's last line must be equal to expectedLastLine
@echo off
setlocal enabledelayedexpansion
set currentDir=%CD%

:: Set variables
set secondWindowTitle=My second window
set exeName=MyExe.exe
set exeFolder=x64/Release
set maxExeRunTime_s=5
set tempOutFile=temp_output.txt
set expectedLastLine=Simulation completed.

cd %exeFolder%
:: Start the program in a new window and redirect output to a file
start "%secondWindowTitle%" cmd /c %exeName% > %tempOutFile%
:: Allow the program some time to run
timeout /t %maxExeRunTime_s%

:: Check if the program window is still open
tasklist /FI "WINDOWTITLE eq %secondWindowTitle%" | find "%exeName%" > NUL
:: If task has finished, the above tasklist command will fail and errorlevel will be 1
if %errorlevel%==1 (
    echo %exeName% finished within %maxExeRunTime_s% seconds.
    echo Get the last line from %tempOutFile%...
    for /F "delims=" %%i in ('type %tempOutFile%) do set lastLine=%%i    
    :: Extract only the text part from the last line
    set "lastLine=%lastLine:*]=%"    
    echo Last line is "%lastLine%"
    echo expected: "%expectedLastLine%"    
    if "%lastLine%"=="%expectedLastLine%" (
        echo The last line was as expected.
    ) else (
        echo The last line was different!
    )
    del %tempOutFile%
) else (
    echo %exeName% exceeded max run time of %maxExeRunTime_s% seconds.    
    taskkill /FI "WINDOWTITLE eq %secondWindowTitle%"
)

:: Return to the original directory
cd %currentDir%