Monte Carlo simulation that calculates probability of winning a die-rolling game. Start with 1 chip, roll a 1, 2, 3, and you lose a chip, roll a 4 or 5, you gain a chip, roll a 6, you gain 2 chips. If you have no chips you lose, 4+ chips you win.

Chip-Game.py

from random import choice
from tqdm import tqdm

trials = 10000000  # number of times the game is played (10,000,000)
lose = 0
win = 0

for game in tqdm(range(1, trials)):
    options = [1, 2, 3, 4, 5, 6]  # can roll any of these numbers
    chips = 1  # starting point for each game

    # continue this loop for as long as you haven't lost or won
    while chips > 0 and chips < 4:
        # picking random number out of options, like rolling a die
        roll = choice(options)
        if roll == 1 or roll == 2 or roll == 3:
            chips -= 1
        elif roll == 4 or roll == 5:
            chips += 1
        elif roll == 6:
            chips += 2
    if chips <= 0:
        lose += 1
    elif chips >= 4:
        win += 1

print(win / lose)