simple e-mail sender using AWS SES

publish.py

#!/usr/bin/env python
import smtplib 
from email.mime.multipart import MIMEMultipart 
from email.mime.text import MIMEText 
from email.mime.base import MIMEBase 
from email import encoders
import sys
import glob
import os

SMTP_USER = os.environ['SMTP_USER']
SMTP_PASS = os.environ['SMTP_PASS']

def part(filename):
  basename = os.path.basename(filename)
  attachment = open(filename, "rb") 
  p = MIMEBase('application', 'octet-stream') 
  p.set_payload((attachment).read()) 
  encoders.encode_base64(p) 
  p.add_header('Content-Disposition', "attachment; filename= %s" % basename) 
  return p

def publish(source, destinations, subject, attachments):
  msg = MIMEMultipart() 
  msg['From'] = source
  msg['To'] = ', '.join(destinations)
  msg['Subject'] = subject 
  body = "Relevant information is in the attached file."
  msg.attach(MIMEText(body, 'plain')) 

  for filename in attachments:
    msg.attach(part(filename))

  smtp = smtplib.SMTP("email-smtp.us-east-1.amazonaws.com", 587)
  #smtp.set_debuglevel(1)
  print (smtp.starttls())
  print (SMTP_USER, SMTP_PASS)
  print (smtp.login(SMTP_USER, SMTP_PASS))
  print (smtp.sendmail(source, destinations, msg.as_string()))

if __name__=='__main__':
  source = sys.argv[1]
  destinations = sys.argv[2].split(';')
  subject = sys.argv[3]
  attachments = sys.argv[4].split(';')
  publish(
    source,
    destinations, 
    subject,
    attachments
  )