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Forked from iRhonin/pydantic_password_field.py
Created September 16, 2022 14:54
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Pydantic Password Field
from typing import Any
from typing import Dict
from typing import Set
from typing import Type
from pydantic import SecretStr
from pydantic.utils import update_not_none
class Password(SecretStr):
"""Pydantic type for password"""
special_chars = {
'$',
'@',
'#',
'%',
'!',
'^',
'&',
'*',
'(',
')',
'-',
'_',
'+',
'=',
'{',
'}',
'[',
']',
}
min_length = 8
includes_special_chars = False
includes_numbers = False
includes_lowercase = False
includes_uppercase = False
@classmethod
def __modify_schema__(cls, field_schema: Dict[str, Any]) -> None:
update_not_none(
field_schema,
minLength=cls.min_length,
includesNumbers=cls.includes_numbers,
includesLowercase=cls.includes_lowercase,
includesUppercase=cls.includes_uppercase,
includesSpecialChars=cls.includes_special_chars,
specialChars=cls.special_chars,
)
@classmethod
def __get_validators__(cls):
yield cls.validate
@classmethod
def validate(cls, v):
if not isinstance(v, str):
raise TypeError('string required')
if len(v) < cls.min_length:
raise ValueError(f'length should be at least {cls.min_length}')
if cls.includes_numbers and not any(char.isdigit() for char in v):
raise ValueError('Password should have at least one numeral')
if cls.includes_uppercase and not any(char.isupper() for char in v):
raise ValueError('Password should have at least one uppercase letter')
if cls.includes_lowercase and not any(char.islower() for char in v):
raise ValueError('Password should have at least one lowercase letter')
if cls.includes_special_chars and not any(
char in cls.special_chars for char in v
):
raise ValueError(
f'Password should have at least one of the symbols {cls.special_chars}'
)
return cls(v)
def conpassword(
*,
min_length: int = 8,
includes_special_chars: bool = False,
special_chars: Set[str] = Password.special_chars,
includes_numbers: bool = False,
includes_lowercase: bool = False,
includes_uppercase: bool = False,
) -> Type[Password]:
# use kwargs then define conf in a dict to aid with IDE type hinting
namespace = dict(
special_chars=special_chars,
min_length=min_length,
includes_special_chars=includes_special_chars,
includes_numbers=includes_numbers,
includes_lowercase=includes_lowercase,
includes_uppercase=includes_uppercase,
)
return type('ConstrainedPassword', (Password,), namespace)
# Usage
from pydantic import BaseModel, ValidationError
class PasswordModel(BaseModel):
password: Password
conpassword: conpassword(
min_length=4,
includes_numbers=True,
includes_lowercase=True,
includes_uppercase=True,
includes_special_chars=True,
special_chars={'@', '%'},
)
password_model = PasswordModel(password='utryeoqq', conpassword='aB3@')
print(password_model)
#> password=SecretStr('**********')
print(password_model.password.get_secret_value())
#> 'utryeoqq'
try:
PasswordModel(password='short', conpassword='1234')
except ValidationError as e:
print(str(e))
"""
2 validation errors for PasswordModel
password
length should be at least 8 (type=value_error)
conpassword
Password should have at least one uppercase letter (type=value_error)
"""
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