python string

string.py

strn = 'abcbaabbcc'
d = {}
k = 2
prev_word = strn[0]
c = 1

for s in strn[1:]:
    if prev_word == s:
        c+=1
        print('this is c = {} in first loop'.format(c))
    else:
        if k == c:
            d[prev_word] = c
            print('this is d = {} in first loop'.format(d))
        c = 1
        prev_word = s
print(d)
for k, v in sorted(d.items()):
    print (k)
    break
    
########################    
from collections import Counter

string = "abcbaabbccc"
counter = Counter(strn)
for key, value in sorted(d.items()):
  if v == k:
    print k
    break

This is simpler:

for i in stri: d[i] = d.get(i, 0)+1 if d[i] == 2: print(i) print('this is the answer') break