Created
November 11, 2017 12:45
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遠心力の微分方程式の数値解 前進・後退オイラー法
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#include <stdio.h> | |
int main() { | |
double xn = 1.0; | |
double yn = 0.0; | |
double t = 0.0; | |
double dt = 0.01; | |
double k = 1.0; | |
double x = xn; | |
double y = yn; | |
for (int i = 0; i < 5000; ++i) { | |
//x = xn - yn * dt; | |
//y = yn + xn * dt; | |
x = (xn - yn * dt) / (1.0 + dt * dt); | |
y = (yn + xn * dt) / (1.0 + dt * dt); | |
xn = x; | |
yn = y; | |
printf("%lf %lf %lf\n", t, x, y); | |
t = t + dt; | |
} | |
return 0; | |
} |
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