Easiest and fastest palyndrome checker

palyndrome.java

import java.io.*;
import java.util.*;

public class Solution {

    public static void main(String[] args) {
        
        Scanner sc=new Scanner(System.in);
        String s=sc.next();
        /* Enter your code here. Print output to STDOUT. 
        for(int i=0; i<s.length()/2; i++){
            if(s.charAt(i) != s.charAt(s.length()-1-i)){
                System.out.println("No");
                System.exit(0);
            }
        }
        System.out.println("Yes");*/
        
        StringBuilder sb= new StringBuilder(s);
        if( s.equals(sb.reverse().toString())){
            System.out.println("Yes");
        }else{
            System.out.println("No");
        }
    }
}