scampbell2434/.block

## .block
license: mit

## README.md

      
    Raw
  

              README.md
            
          
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## index.html
<!DOCTYPE html>
<head>
  <meta charset="utf-8">
  <script src="https://d3js.org/d3.v4.min.js"></script>
  <style>
    body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
  </style>
</head>

<body>
  <h1>Please look in the code below for 5 JavaScript practice problems.</h1>
  <p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
  <script>
  // Problem 1: modify array1 so that each object it contains includes the 2 letter state "id"

  array1 = [
    				{name: "Arizona",  location: "Southwest"},
           	{name: "Virginia", location: "East"},
            {name: "Florida",  location: "Southeast"}
           ];

  array2 = [
            {name: "Virginia", id: "VA"},
    				{name: "Arizona", id: "AZ"},
            {name: "Florida", id: "FL"}
  				 ];

  array1.forEach(function(a1) {
    array2.forEach(function(a2) {
      if (a1.name == a2.name) {
        a2.id = a1.id;
      }
  	})
  })

  // Problem 2: print all items that are in both array3
  // and array4 to the console.

  array3 = ['a','b','c','d'];
  array4 = ['a','c','e','f','g'];

  // console.log("first solution:")
  array3.forEach(function (a3) {
    array4.forEach(function (a4) {
      if (a3 == a4) {
        // console.log(a3)
      }
    })
  })

  // console.log("second solution:")
  array3.forEach(function (a3) {
    if (array4.includes(a3)) {
        // console.log(a3);
        }
  })

  // Problem 3: 'states' is an array of objects. Sort the array in ascending order by population

  states = [{name: "Alaska", id: "AK", population: 741894},
            {name: "Virginia", id: "VA", population: 8411808},
    				{name: "Arizona", id: "AZ", population: 6931071},
            {name: "Florida", id: "FL", population: 20984400}]
  states.sort(function (a,b){ return a.population - b.population})

  // Problem 4: using console.log() and the appropriate index on the sorted 'states' array, print the state with the smallest population.

  console.log


  // someNumbers is an array containing all integers from 1-10 inclusively
  someNumbers = d3.range(1,11)

  // Problem 5: using console.log(), a loop,and the modulus operator, print those members of someNumbers that are NOT multiples of 3.


  </script>
</body>
	<!DOCTYPE html>
	<head>
	<meta charset="utf-8">
	<script src="https://d3js.org/d3.v4.min.js"></script>
	<style>
	body { margin:0;position:fixed;top:0;right:0;bottom:0;left:0; }
	</style>
	</head>

	<body>
	<h1>Please look in the code below for 5 JavaScript practice problems.</h1>
	<p>(These problems don't include any SVG manipulation, so you will need to open the developer console in order to see the output of your code)</p>
	<script>
	// Problem 1: modify array1 so that each object it contains includes the 2 letter state "id"

	array1 = [
	{name: "Arizona", location: "Southwest"},
	{name: "Virginia", location: "East"},
	{name: "Florida", location: "Southeast"}
	];

	array2 = [
	{name: "Virginia", id: "VA"},
	{name: "Arizona", id: "AZ"},
	{name: "Florida", id: "FL"}
	];

	array1.forEach(function(a1) {
	array2.forEach(function(a2) {
	if (a1.name == a2.name) {
	a2.id = a1.id;
	}
	})
	})

	// Problem 2: print all items that are in both array3
	// and array4 to the console.

	array3 = ['a','b','c','d'];
	array4 = ['a','c','e','f','g'];

	// console.log("first solution:")
	array3.forEach(function (a3) {
	array4.forEach(function (a4) {
	if (a3 == a4) {
	// console.log(a3)
	}
	})
	})

	// console.log("second solution:")
	array3.forEach(function (a3) {
	if (array4.includes(a3)) {
	// console.log(a3);
	}
	})

	// Problem 3: 'states' is an array of objects. Sort the array in ascending order by population

	states = [{name: "Alaska", id: "AK", population: 741894},
	{name: "Virginia", id: "VA", population: 8411808},
	{name: "Arizona", id: "AZ", population: 6931071},
	{name: "Florida", id: "FL", population: 20984400}]
	states.sort(function (a,b){ return a.population - b.population})

	// Problem 4: using console.log() and the appropriate index on the sorted 'states' array, print the state with the smallest population.

	console.log


	// someNumbers is an array containing all integers from 1-10 inclusively
	someNumbers = d3.range(1,11)

	// Problem 5: using console.log(), a loop,and the modulus operator, print those members of someNumbers that are NOT multiples of 3.



	</script>
	</body>