Offensive word detection in Python 3 via Wiktionary lists

isOffensive.py

import urllib.request
import json

def isOffensive(word):
	"""
	Determines whether a word string is considered offensive.
	Searches the word on Wiktionary, then iterates through all the 'Categories' the word belongs to.
	If the category name contains a word related to 'offensive', the function returns True
	"""
	wikiUrl = "http://en.wiktionary.org/w/api.php?format=json&action=query&prop=categories&redirects=1&titles="
	qContinue=""
	while(True):
		#Continue making HTTP requests for the word category lists until no more pages of categories exist
		url = wikiUrl+word+("&clcontinue="+urllib.parse.quote(qContinue) if qContinue!="" else "")
			#The continue attribute sometimes contains pipes (|) which must be escaped by quote()
		rawQuery = urllib.request.Request(url)						#Make the HTTP request
		response = urllib.request.urlopen(rawQuery)					#Parse it into a readable
		wikiQuery = json.loads(response.readall().decode('utf-8'))	#JSON format
		try: 
			#Save the continue attribute to append to the next search
			qContinue = wikiQuery["continue"]["clcontinue"]
		except KeyError:
			#when "continue" doesn't exist, i.e. no more pages, the function can quit
			qContinue = "" 
		categories = wikiQuery["query"]["pages"][list(wikiQuery["query"]["pages"])[0]]["categories"]
			#the key between "pages" and "categories" is a random number, e.g. ["query"]["pages"]["3076"]["categories"]
		for category in categories:
			title = category["title"]
			print(title)
			bannedCats = ["offensive", "swear", "vulgarities", "slurs", "derogatory", "slang"]
				#if the category title contains any of these words, return True	
			if any(x in title.lower() for x in bannedCats):
				print("SKIPPING")
				return True
		if (qContinue == ""):
			print("Not offensive")
			return False