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@schamblee
Created May 26, 2018 17:02
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Even or odd
function isEven(value){
if (value % 2 == 0){
return true;
}
else
return false;
}
Constant Time O(1)
Are you here?
function areYouHere(arr1, arr2) {
for (let i=0; i<arr1.length; i++) {
const el1 = arr1[i];
for (let j=0; j<arr2.length; j++) {
const el2 = arr2[j];
if (el1 === el2) return true;
}
}
return false;
}
Polynomial Time O(n^2)
function doubleArrayValues(array) {
for (let i=0; i<array.length; i++) {
array[i] *= 2;
}
return array;
}
Linear Time O(n)
function naiveSearch(array, item) {
for (let i=0; i<array.length; i++) {
if (array[i] === item) {
return i;
}
}
}
Linear Time O(n)
function createPairs(arr) {
for (let i = 0; i < arr.length; i++) {
for(let j = i+1; j < arr.length; j++) {
console.log(arr[i] + ", " + arr[j] );
}
}
}
Polynomial Time O(n^2)
function generateFib(num) {
let result = [];
for (let i = 1; i <= num; i++) {
// we're adding the first item
// to the result list, append the
// number 0 to results
if (i === 1) {
result.push(0);
}
// ...and if it's the second item
// append 1
else if (i == 2) {
result.push(1);
}
// otherwise, sum the two previous result items, and append that value to results.
else {
result.push(result[i - 2] + result[i - 3]);
}
}
// once the for loop finishes
// we return `result`.
return result;
}
Linear Time O(n)
function efficientSearch(array, item) {
let minIndex = 0;
let maxIndex = array.length - 1;
let currentIndex;
let currentElement;
while (minIndex <= maxIndex) {
currentIndex = Math.floor((minIndex + maxIndex) / 2);
currentElement = array[currentIndex];
if (currentElement < item) {
minIndex = currentIndex + 1;
}
else if (currentElement > item) {
maxIndex = currentIndex - 1;
}
else {
return currentIndex;
}
}
return -1;
}
Logarithmic O(log(n))
function findRandomElement(arr) {
return arr[Math.floor(Math.random() * arr.length)];
}
Constant Time O(1)
function isPrime(n) {
// if n is less than 2 or a decimal, it's not prime
if (n < 2 || n % 1 != 0) {
return false;
}
// otherwise, check if `n` is divisible by any integer
// between 2 and n.
for (let i = 2; i < n; ++i) {
if (n % i == 0) return false;
}
return true;
}
Linear Time O(n)
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