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@schmohlio
Last active August 29, 2015 14:19
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finding max number of meeting rooms
meetings_sample = [(0, 30), (60, 90), (20, 65)]
[(0,True),(30,False),(60,True),(90,False),(20,True),(65,False)]
def count_rooms(meeting_events):
meeting_events.sort(lambda x,y: x[0]<y[0]) # O(nlogn), need to add sorting here so that False is first
# not sure if that sort is left associative or right
# associative
ongoing_meetings = [] # pretend stack
max_num_meetings = 0 # initialize
stack_size = 0
for time, is_start in meeting_events
if (is_start):
ongoing_meetings.append((time))
stack_size += 1
else:
ongoing_meetings.pop()
stack_size -= 1
max_num_meetings = max(max_num_meetings, stack_size)
return max_num_meetings
# return True if overlap in meetings
def has_overlap(meetings):
meetings.sort(key= lambda x: x[0]) # O(nlogn)
prev_end_time = -1
for start, end in meetings:
if start < prev_end_time:
return true
else:
prev_end_time = end
return false
@schmohlio
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I think the count_rooms() at line 38 might be more efficient due to O(1) additional space, since it doesnt have stack?

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