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While writing a redux reducer I ran into the issue that I wanted to remove a property from an object without mutating it. Here's how I solved it. tl;dr Just use http://devdocs.io/lodash/index#omit #redux #reducers #immutability
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import test from 'ava' | |
import deepFreeze from 'deep-freeze' | |
import omit from 'lodash/omit' | |
test('normal delete will mutate the object', t => { | |
const obj = { a: 1, b: 2 } | |
deepFreeze(obj) | |
t.throws(() => delete obj.a) | |
}) | |
test('naive implementation #1', t => { | |
function immutableDelete (obj, prop) { | |
const obj2 = {} | |
Object.keys(obj) | |
.filter(key => key !== prop) | |
.forEach(key => obj2[key] = obj[key]) | |
return obj2 | |
} | |
const obj = { a: 1, b: 2 } | |
deepFreeze(obj) | |
const obj2 = immutableDelete(obj, 'a') | |
t.same(obj2, { b: 2 }) | |
}) | |
test('naive implementation #2', t => { | |
function immutableDelete (obj, prop) { | |
return Object.keys(obj) | |
.filter(key => key !== prop) | |
.reduce((obj2, key) => { | |
obj2[key] = obj[key] | |
return obj2 | |
}, {}) | |
} | |
const obj = { a: 1, b: 2 } | |
deepFreeze(obj) | |
const obj2 = immutableDelete(obj, 'a') | |
t.same(obj2, { b: 2 }) | |
}) | |
test('ah I can just use _.omit', t => { | |
const obj = { a: 1, b: 2 } | |
deepFreeze(obj) | |
const obj2 = omit(obj, 'a') | |
t.same(obj2, { b: 2 }) | |
}) |
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