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Largest remainder round
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/** | |
* largestRemainderRound will round each number in an array to the nearest | |
* integer but make sure that the the sum of all the numbers still equals | |
* desiredTotal. Uses largest remainder method. Returns numbers in order they | |
* came. | |
* | |
* @param {number[]} numbers - numbers to round | |
* @param {number} desiredTotal - total that sum of the return list must equal | |
* @return {number[]} the list of rounded numbers | |
* @example | |
* | |
* var numbers = [13.6263, 47.9896, 9.5960, 28.7880]; | |
* largestRemainderRound(numbers, 100); | |
* | |
* // => [14, 48, 9, 29] | |
* | |
*/ | |
function largestRemainderRound(numbers, desiredTotal) { | |
var result = numbers.map(function(number, index) { | |
return { | |
floor: Math.floor(number), | |
remainder: getRemainder(number), | |
index: index, | |
}; | |
}).sort(function(a, b) { | |
return b.remainder - a.remainder; | |
}); | |
var lowerSum = result.reduce(function(sum, current) { | |
return sum + current.floor; | |
}, 0); | |
var delta = desiredTotal - lowerSum; | |
for (var i = 0; i < delta; i++) { | |
result[i].floor++; | |
} | |
return result.sort(function(a, b) { | |
return a.index - b.index; | |
}).map(function(result) { | |
return result.floor; | |
}); | |
} | |
function getRemainder(number) { | |
var remainder = number - Math.floor(number); | |
return remainder.toFixed(4); | |
} |
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Thank you!
The only thing is - i wouldnt use reminder.toFixed(4) since it returns a formatted string. instead i woul use Math.round(reminder * 1000)/1000
here is a bit modified code, now you can pass whole numbers and denominator and you will get output of rounded divided numbers by denominator