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August 13, 2017 23:22
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The knapsack problem
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import java.util.ArrayList; | |
import java.util.Arrays; | |
import java.util.List; | |
/** | |
* Problem: Write a program for knapsack problem that selects a subset of items that has maximum value and satisfies | |
* the weight constraint. All items have integer weights and value | |
*/ | |
public class KnapsackProblem { | |
public static class Item { | |
public Integer value; | |
public Integer weight; | |
public Item(Integer weight, Integer value) { | |
this.value = value; | |
this.weight = weight; | |
} | |
} | |
public static void main(String[] argv) { | |
List<Item> itemList = Arrays.asList( | |
new Item(1, 1), | |
new Item(3, 4), | |
new Item(4, 5), | |
new Item(5, 7) | |
); | |
KnapsackProblem problem = new KnapsackProblem(); | |
int result = problem.optimumSubjectToCapacity(itemList, 7); | |
System.out.println("Result " + result); | |
} | |
/** | |
If you had 4 items (weight:1,value:1),(weight:3,value:4),(weight:4,value:5),(weight:5,value:7) and want to pickup | |
max weight of 7 | |
Create DP table of [numberofItems+1][capacity+1] | |
Now check what would get more value, choosing this weight or ignoring this weight using following formula | |
if(column < weight[row-1]) | |
dptable[row][column] = dptable[row-1][column] | |
else | |
dptable[row][column] = Math.max( dpTable[row-1][column] ,without this weight | |
value[row-1] + dptable[row-1][column-weight[row-1] with this weight | |
) | |
[0, 0, 0, 0, 0, 0, 0, 0] | |
[0, 1, 1, 1, 1, 1, 1, 1] | |
[0, 1, 1, 4, 5, 5, 5, 5] | |
[0, 1, 1, 4, 5, 6, 6, 9] | |
[0, 1, 1, 4, 5, 7, 8, 9] | |
*/ | |
public int optimumSubjectToCapacity(List<Item> itemList, int capacity) { | |
int[][] value = new int[itemList.size() + 1][capacity + 1]; | |
for (int row = 0; row <= itemList.size(); row++) { | |
for (int column = 0; column <= capacity; column++) { | |
if (row == 0 || column == 0) { | |
value[row][column] = 0; | |
} else { | |
if (column < itemList.get(row-1).weight) { | |
value[row][column] = value[row - 1][column]; | |
} else { | |
int withoutItem = value[row - 1][column]; | |
int remainingItemValue = column - itemList.get(row-1).weight; | |
int withItem = itemList.get(row-1).value + value[row - 1][remainingItemValue]; | |
value[row][column] = Math.max(withoutItem, withItem); | |
} | |
} | |
} | |
} | |
List<Item> pickedItemList = new ArrayList<>(); | |
return value[itemList.size() - 1][capacity]; | |
} | |
private void printDPTable(int[][] dpTable) { | |
for (int[] row : dpTable) { | |
System.out.println(Arrays.toString(row)); | |
} | |
} | |
} |
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