Last active
December 7, 2018 00:14
-
-
Save seisvelas/4e5188567386a8dfe18485aa2880f3d2 to your computer and use it in GitHub Desktop.
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
import timeit | |
from numpy import mean | |
nqueens_gen_setup = """def threatened(pos, past, n): | |
for i in range(len(past)): | |
if past[i] == pos or abs(pos - past[i]) == len(past) - i: | |
return True | |
return False | |
def nqueens(n, past=None): | |
if past == None: | |
for i in range(n): | |
yield from nqueens(n, [i+1]) | |
else: | |
if len(past) == n: | |
yield past[:] | |
else: | |
for pos in range(1,n+1): | |
if not threatened(pos, past, n): | |
yield from nqueens(n,past + [pos]) | |
list(nqueens(8))""" | |
nqueens_global_setup = """ | |
solutions = [] | |
def threatened(pos, past, n): | |
for i in range(len(past)): | |
if past[i] == pos or abs(pos - past[i]) == len(past) - i: | |
return True | |
return False | |
def nqueens(n, past=None): | |
if past == None: | |
return [nqueens(n, [i+1]) for i in range(n)] | |
if len(past) == n: | |
solutions.append(past) | |
else: | |
[nqueens(n, past + [pos]) for pos in range(1, n+1) if not threatened(pos, past, n)] | |
nqueens(8) | |
""" | |
print(mean(timeit.Timer(setup=nqueens_gen_setup).repeat(20, 1))) | |
print(mean(timeit.Timer(setup=nqueens_global_setup).repeat(20,1))) | |
## I played with the numbers of repeats, nqueens_gen_setup is slightly faster every time. But I bet I could cut the speed on | |
## nqueens_gobal_setup to be more competitive! |
This file contains bidirectional Unicode text that may be interpreted or compiled differently than what appears below. To review, open the file in an editor that reveals hidden Unicode characters.
Learn more about bidirectional Unicode characters
solutions = [] | |
def threatened(pos, past, n): | |
for i in range(len(past)): | |
if past[i] == pos or abs(pos - past[i]) == len(past) - i: | |
return True | |
return False | |
def nqueens(n, past=None): | |
if past == None: | |
return [nqueens(n, [i+1]) for i in range(n)] | |
if len(past) == n: | |
solutions.append(past) | |
else: | |
[nqueens(n, past + [pos]) for pos in range(1, n+1) if not threatened(pos, past, n)] | |
nqueens(8) | |
print(len(solutions)) |
Sign up for free
to join this conversation on GitHub.
Already have an account?
Sign in to comment