Tic tac toe in python

tictactoe.py

from itertools import chain
from sys import exit

BOARD_TEMPLATE = '''
   |   |   
 {} | {} | {} 
   |   |   
---+---+---
   |   |   
 {} | {} | {} 
   |   |   
---+---+---
   |   |   
 {} | {} | {} 
   |   |   
'''

PRINT_MAPPINGS = [ ' ', 'X', 'O' ]

# 0 is empty
# 1 is player 1 (X)
# 2 is player 2 (O)
board = [
    [0, 0, 0],
    [0, 0, 0],
    [0, 0, 0]
]

turn = 1

def print_board():
    l = [ PRINT_MAPPINGS[el] for row in board for el in row ]
    print(BOARD_TEMPLATE.format(*l))

def check():
    checks = [check_hor(), check_ver(), check_diag()]

    if any(check for check in checks):
        win()

def check_hor():
    return any(row == [turn, turn, turn] for row in board)

def check_ver():
    columns = [ [ row[i] for row in board ] for i in range(3) ]
    return any(col == [turn, turn, turn] for col in columns)

def check_diag():
    diag = [
        [ board[0][0], board[1][1], board[2][2] ],
        [ board[0][2], board[1][1], board[2][0] ]
    ]
    return any(d == [turn, turn, turn] for d in diag)

def win():
    print_board()
    print(f'player {turn} wins!')
    exit()

def tie():
    print_board()
    print('tie!')

def prompt():
    global turn

    print_board()
    inp = int(input(f'player {turn}: ')) - 1
    pos = ( inp // 3, inp % 3 )

    if inp > len(list(chain(*board))) - 1 or inp < 0:
        print('That is not a valid space.\n')
        return

    if board[pos[0]][pos[1]] != 0:
        print('That space is already taken!\n')
        return

    board[pos[0]][pos[1]] = turn
    check()
    turn = 2 if turn == 1 else 1

while any(el == 0 for el in list(chain(*board))):
    prompt()
tie()

Just created something like this, thank you for uploading.

Just created something like this, thank you for uploading.

No problem!