sqrt.py

# Takes any number of arguments and outputs 
# the number that, to the power of 1/2 (or sqrt
# function), is equal to the input.
# 
# Author: Soeren Gade
# Date: 04.05.2014
# License: MIT

# Imported stdlibs
import sys
import math

# The main operation
def getSqrtedNumber(sqrt):
	''' Returns the number of which the user provided the sqrt.
		Also returns a checksum, that should equal the input value. '''
	pow = math.pow(sqrt, 2)
	return pow, math.sqrt(pow)	# ### Returns ###
								# 1. The src number. sqrt^2
								# 2. The sqrt of the src number.
								# 	 	The 'checksum' of the input
	
# Go through each arg
# Start at 1 to skip the filename itself passed to python
for x in range(1, len(sys.argv)):
	# Get the input as float. Precision is needed!
	sqrt = float(sys.argv[x])
	# Get the number and the check number from our function
	num, sqrtCheck = getSqrtedNumber(sqrt)
	print "sqrt(", num, ") = ", sqrt
	# Check if the sqrt of the number we give the user
	# really is the number the user gave us.
	# Otherwise, we probably have some error with floats. :(
	if not sqrtCheck == sqrt:
		print "=== Check Error:", sqrtCheck
		
# Tell how many arguments there really were to check
print "Done. Checked", ( len(sys.argv) - 1 ), "argument(s)."