Created
June 11, 2015 04:20
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POC of Longest Increasing Sub-Sequence with complexity O(mn)
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/* References : | |
http://www.geeksforgeeks.org/dynamic-programming-set-3-longest-increasing-subsequence/ | |
https://www.youtube.com/watch?v=4fQJGoeW5VE */ | |
#include <iostream> | |
#include <algorithm> | |
#include <vector> | |
using namespace std; | |
int lis(vector<int> &A) | |
{ | |
vector<vector<int> > L{A.size()}; | |
int max = 1; | |
L[0].push_back(A[0]); | |
for(int i = 1; i < A.size(); i++) | |
{ | |
for(int j = 0; j < i; j++) | |
if(A[j] < A[i] && L[j].size() > L[i].size()) | |
L[i] = L[j]; | |
L[i].push_back(A[i]); | |
} | |
for(auto x: L) | |
{ | |
max = std::max(max, (int)x.size()); | |
for(auto b: x) | |
cout << b << " "; | |
cout << endl; | |
} | |
return max; | |
} | |
int main() | |
{ | |
vector<int> A = {1, -3, -2, 5, -6, 7, 10, -16}; | |
cout << "\n lis -> " << lis(A) << endl; | |
} |
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