Created
August 22, 2012 02:06
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grep an accesslog(apache) file within a specific time period
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| $ cat ACCESS_LOG | awk '$4 >= "[29/Jan/2012:12:00:00" && $4 < "[29/Jan/2012:13:00:00"' |
Works great!
When the time format in the log is like [Tue Feb 05 09:59:54 2019]. It needs to be matched like bellow, because column $4 just contains the time.
Between 9am and 10am:
$ cat ACCESS_LOG | awk '$4 >= "09:00:00 2019" && $4 < "10:00:00"'
That's great. Is there a quick way to throw a bash variable in there?
eg. yesterday - date +%d/%b/%Y --date="yesterday" - which gives 07/Apr/2019
and today - date +%d/%b/%Y - which gives 06/Apr/2019
i think that script not valid because the weight of days is larger then weight of years and month
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works like a charm. Thanks.