计算之道，京东/人人场，第一题 python2.7.9解。

print_days_range

import datetime


base_dict = {
    '0': 6,
    '1': 2,
    '2': 5,
    '3': 5,
    '4': 4,
    '5': 5,
    '6': 6,
    '7': 3,
    '8': 7,
    '9': 6}
group_number = input()
total_list = []

__i = 0
while True:
    total_list.append(input())
    __i += 1
    if __i >= group_number * 2:
        break


for x, y in zip(*[iter(total_list)]*2):
    # x is start time
    # y is endtime number
    x = str(x)
    start_time = datetime.date(int(x[:4]), int(x[4:6]), int(x[6:]))
    endtime = start_time
    while endtime < datetime.date(2999, 12, 31):
        endtime = endtime + datetime.timedelta(days=1)
        _string = str(endtime.year) + '%02d' % endtime.month + '%02d' % endtime.day
        total = 0
        for i in _string:
            total += base_dict[i]
        if total == y:
            print((endtime - start_time).days)
            break
    if endtime >= datetime.date(2999, 12, 31):
        print('-1')