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Bash script to calculate MySQL table dimensions on disk
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#!/bin/bash | |
( | |
mysql_datadir=$(grep datadir /etc/my.cnf | head -n 1 | cut -d "=" -f 2 | cut -d "#" -f 1) | |
cd $mysql_datadir | |
for frm_file in $(find . -name "*.frm" | egrep -v "[.]/(mysql|sys|performance_schema|common_schema)") | |
do | |
table_schema=$(echo $frm_file | cut -d "/" -f 2) | |
table_name=$(echo $frm_file | cut -d "/" -f 3 | cut -d "." -f 1) | |
if [ -f ${frm_file//.frm/.MYD} ]; then | |
# A MyISAM table | |
# This script only supports an unpartitioned table | |
file_size=$(du -cb ${frm_file//.frm/.MY?} 2> /dev/null | tail -n 1) | |
elif [ -f ${frm_file//.frm/.ARZ} ]; then | |
# An ARCHIVE table | |
# This script only supports an unpartitioned table | |
file_size=$(du -cb ${frm_file//.frm/.ARZ} 2> /dev/null | tail -n 1) | |
else | |
# Is this InnoDB? | |
tbl_file=${frm_file//.frm/.ibd} | |
if [ -f $tbl_file ] | |
then | |
# unpartitioned table | |
file_size=$(du -cb $tbl_file 2> /dev/null | tail -n 1) | |
else | |
# attempt partitioned innodb table | |
# Yeah, maybe this isn't InnoDB at all, and this clause also catches that. Oh, well... | |
tbl_file_partitioned=${frm_file//.frm/#*.ibd} | |
file_size=$(du -cb $tbl_file_partitioned 2> /dev/null | tail -n 1) | |
fi | |
fi | |
file_size=${file_size//total/} | |
echo "$table_schema.$table_name" $file_size | |
done | |
) | sort -k 2 -nr | head -n 100 | while read entry size | |
do | |
echo $entry $size | |
done |
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