Created
July 7, 2012 09:53
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Prime Factors Kata 4th iteration
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module PrimeFactorDecomposer | |
def decompose(number) | |
return [number] if prime?(number) | |
primes = [] | |
2.upto(number / 2) do |candidate| | |
while (number % candidate).zero? do | |
primes << candidate | |
number = number / candidate | |
end | |
end | |
primes | |
end | |
def prime?(number) | |
return false if number == 1 | |
(2..Math.sqrt(number)).each do |i| | |
return false if (number %i).zero? | |
end | |
true | |
end | |
end |
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describe PrimeFactorDecomposer do | |
include PrimeFactorDecomposer | |
it "returns no prime factors for 1" do | |
decompose(1).should be_empty | |
end | |
it "decomposes 2 into 2" do | |
decompose(2).should be == [2] | |
end | |
it "decomposes 3 into 3" do | |
decompose(3).should be == [3] | |
end | |
it "decomposes 4 into 2,2" do | |
decompose(4).should be == [2,2] | |
end | |
it "decomposes 5 into 5" do | |
decompose(5).should be == [5] | |
end | |
it "decomposes 12 into 2,2,3" do | |
decompose(12).should be == [2,2,3] | |
end | |
end |
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PrimeFactorDecomposer | |
returns no prime factors for 1 | |
decomposes 2 into 2 | |
decomposes 3 into 3 | |
decomposes 4 into 2,2 | |
decomposes 5 into 5 | |
decomposes 12 into 2,2,3 | |
Finished in 0.00441 seconds | |
6 examples, 0 failures |
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I like better how this reads now. The case that Nikolai discovered https://gist.github.com/3045485/1fc71bf3fd39e0943661e5c50769e5829f6a2ccf is fixed now.
It seems the prime? part is needed in order for this to work.
Also i am not sure if the module approach is the best one. The tests read beautiful at least.. I need a few more iterations to know i guess.