次のデュオトリオの組み合わせを勝手に見つける

combination_of_duotrio.py

import random

aqours = ["千歌", "梨子", "果南", "ダイヤ", "曜", "善子", "花丸", "鞠莉", "ルビィ"]


def check(combi):
    if set(combi) == ("千歌", "果南") or \
        set(combi) == ("善子", "曜") or \
        set(combi) == ("ダイヤ", "ルビィ") or \
        set(combi) == ("花丸", "鞠莉", "梨子"):
        return False
    else:
        return True


duo1 = random.sample(aqours, 2)
print("1:", duo1)
rest1 = list(set(aqours) - set(duo1))

duo2 = random.sample(rest1, 2)
print("2:", duo2)
rest2 = list(set(rest1) - set(duo2))

duo3 = random.sample(rest2, 2)
print("3:", duo3)
trio = list(set(rest2) - set(duo3))

print("trio:", trio)

print("既存じゃない？:", "OK" if(check(duo1) and check(duo2) and check(duo3) and check(trio)) else "NG")

$ python random_duotrio.py
1: ['鞠莉', '果南']
2: ['千歌', 'ルビィ']
3: ['梨子', 'ダイヤ']
trio: ['花丸', '善子', '曜']
既存じゃない？: OK

木探索くらいしろよって話ですよね・・