Created
January 18, 2020 13:00
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n-queen algorithm animated in the terminal
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from time import sleep | |
from os import system | |
""" | |
After spending the day trying to understand this algorithm, i decided to animated it in terminal. | |
Makes a lot more sense, so sharing. | |
""" | |
delay = .05 | |
def n_queens(n): | |
def solve_n_queens(row, col_placement): | |
if row == n: | |
print("HURRAH!") | |
sleep(1) | |
result.append(col_placement.copy()) | |
return | |
for col in range(n): | |
# Test if a newly placed queen will conflict | |
# any earlier queens placed before. | |
conflict = False | |
cols_to_backtest = col_placement[:row] | |
to_test = col_placement[:] | |
to_test[row] = col | |
for i, c in enumerate(cols_to_backtest): | |
if abs(c - col) in (0, row - i): | |
conflict = True | |
break | |
print('\n'*5) | |
system('clear') | |
if not conflict: | |
col_placement[row] = col | |
draw_board(col_placement) | |
sleep(delay) | |
solve_n_queens(row + 1, col_placement[:]) | |
else: | |
draw_board(to_test, row, col, conflict) | |
sleep(delay) | |
result = [] | |
solve_n_queens(0, [-1] * n) | |
return result | |
def comp(a, b): | |
return sorted(a) == sorted(b) | |
def draw_board(queens, row=-1, col=-1, conflict=False): | |
n = len(queens) | |
for i in range(n): | |
print(' |', end='') | |
for j in range(n): | |
print('---|', end='') | |
print('') | |
if queens[i] != -1: | |
print(f' {queens[i]} |', end='') | |
else: | |
print(f' |', end='') | |
for j in range(n): | |
if queens[i] == j: | |
c = 'o' | |
if i == row and j == col: | |
c = '.' | |
if conflict: | |
c = 'x' | |
else: | |
c = ' ' | |
print(' {} |'.format(c), end='') | |
print('') | |
system('clear') | |
for queens in n_queens(6): | |
draw_board(queens) | |
print(' '+'-'*17) | |
pass |
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