david.jl

m = 1
n = 4*m + 1

a(j) = (1/n)*(1 + sin((2*π*j*m + π*j)/n)/sin((π*j)/n))

function b(j)
    s = 2
    for k = 1:m
        s += 2*cos((2*π*k*j)/n)
    end
    return s/n
end

println(a(1) - a(2) + a(3) - a(4) + a(5))
println(b(1) - b(2) + b(3) - b(4) + b(5))

for j = 1:n
    println(a(j))
    println(b(j))
end