Gulp require snippet for all devDependencies

Gulpfile.js

gulp = require('gulp');
pkg = require('./package.json');

for (k in pkg.devDependencies) {
  v = pkg.devDependencies[k];
  a = k.indexOf('gulp-') > -1 ? k.split('gulp-')[1] : k;
  GLOBAL[a] = require(k);
}

Same goal, but using matchdep

require('matchdep')
  .filterDev('gulp-*')
  .forEach(function(module) {
    global[module.replace(/^gulp-/, '')] = require(module);
  });

Coffeescript just in case

pkg = require './package.json'
GLOBAL[k.replace(/^gulp-/, '')] = require(k) for k, v of pkg.devDependencies

@kewah why not filter it from package.json too?

require('matchdep')
  .filterDev('gulp-*', './package.json')
    .forEach(function(module) {
      global[module.replace(/^gulp-/, '')] = require(module);
    });

@stryju by default it loads the nearest package.json

@kewah ah, true! my bad :)

// load all gulp tasks matching the `gulp*` pattern to include gulp itself
require('matchdep')
    .filterDev('gulp*') //by default it loads the nearest package.json
    .forEach(function(module) {
        global[module.replace(/^gulp-/, '')] = require(module);
    });